PHP_displayingfromSQL

$dbhost = 'localhost';
$dbuser = 'db4133414';
$dbpass = 'db4133414';
$dbname = 'db4133414';
$conn = new mysqli($dbhost, $dbuser, $dbpass, $dbname);
if ($conn->connect_error) {
    echo "Connection failed<br/>";
    die("Connection failed: " . $conn->connect_error);
}
$sql = "select * from employee";
$result = $conn->query($sql);
while($row = $result->fetch_assoc())
{
    echo $row["firstname"];
    echo $row["surname"];
    echo " \n";
}
$conn->close();