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May 8th, 2016
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  1. $db_host = "localhost";
  2. $db_user = "root";
  3. $db_pass = "";
  4. $db_name = "new_db";
  5. define ("IMG" , "img");
  6.  
  7. $link = mysqli_connect($db_host , $db_user , $db_pass , $db_name) OR DIE ("Не могу подключится");
  8. if (mysqli_connect_errno()) {
  9. printf("Ошибка соединения: %sn", mysqli_connect_error());
  10. exit;
  11. }
  12. $query = mysqli_select_db($link , $db_name) OR DIE ("Не моу выбрать базу, либо она отсутствует");
  13.  
  14. $result = mysqli_query($link , "SELECT `title` , `text` , `img` FROM `news` ");
  15.  
  16. while($row = $result->fetch_assoc())
  17. {?>
  18. <div class="post">
  19. <h2><?= $row['title'];?></h2>
  20. <img src="IMG/<?= $row['img'];?>" title="" />
  21. <p><?= $row['text'];?></p>
  22. </div>
  23. <?}?>
  24.  
  25. $db_host = "localhost";
  26. $db_user = "root";
  27. $db_pass = "";
  28. $db_name = "new_db";
  29.  
  30. mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
  31. $link = mysqli_connect($db_host , $db_user , $db_pass , $db_name);
  32.  
  33. $result = mysqli_query($link , "SELECT `title` , `text` , `img` FROM `news` ");
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