Equal Sums Even Odd Position JS

function equalSumsEvenOddPosition(input) {
    let start = Number(input[0]);
    let end = Number(input[1]);

    let buff = "";
    for (let currentNumber = start; currentNumber <= end; currentNumber++) {
        let currNumString = currentNumber.toString();

        let evenSum = 0;
        let oddSum = 0;

        for (let index = 0; index < currNumString.length; index++) {
           let currentDigit = Number(currNumString[index]);
           let position = index + 1;

            if (position % 2 === 0) {
                evenSum += currentDigit;
            } else {
                oddSum += currentDigit;
            }
        }
            if (evenSum === oddSum) {
            buff += `${currNumString} `
            }
    }
    console.log(buff);
}