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Jan 19th, 2018
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  1. int numA =1;
  2. int numB = 1;
  3. for (int i = 1; i < 1000; i++){
  4. for (int j = 1; j < 1000; j++){
  5. (i + j + Math.sqrt((i^2) + (j^2))) == numA;
  6. }
  7.  
  8. }
  9. /*while (((1000 * ((1000 - (2 * num))/(2 *(1000 * num)))) % 1) != 0){
  10. num++;
  11. }*/
  12. return numA;
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