#include<iostream>
#include<string>
#include<math.h>
using namespace std;
int parseInt(string&);

//turns any string that can be turned into a positive integer,
//into a positive integer.
//returns -1 as an error message if string contains anything but digits
//otherwise returns the integer.
//WORKS ONLY IN BASE-10!!!!!!!!!
//... you heard that, you hexadecimal wankers...
int parseInt(string& s)
{
    //initialize the value to be returned
    int value = 0;
    int a=0;
    int b=0;
    //loop through the argument string
    for(int i=0;i<s.length();i++)
    {
        //if the character in slot i is a digit, that is a whole number
        //greater or equal to zero, and less or equal to nine
        //do following
        if(s.at(i)>='0' && s.at(i) <= '9')
        {
            //typecasting a char to an int gives the ASCII value of said char
            //since number 0 is ASCII 48, subtracting 48 from the ASCII value
            //of the character '0' ends us up with the actual integer 0.
            //same applies for 1, 2, 3 and so on.
            cout << "i=" << i << endl;
            cout << "(int)(s.at(i)-48 = " << (s.at(i)-48) << endl;
            cout << "pow(10,s.length()-(i+1) = " << (pow(10,s.length()-(i+1))) << endl;
            a=(s.at(i)-48);
            cout << "a=" << a << endl;
            b=(pow(10,s.length()-(i+1)));
            cout << "b=" << b << endl;
            value=value+a*b;
            cout << "value before modification: " << value << endl;
            value = value + /*(int)*/((s.at(i)-48))*(pow(10,s.length()-(i+1)));
            cout << "Value after modification " << value << endl;
        }
        else
        {
            return -1;
        }
    }
    return value;
}

int main()
{
    string input = "";
    cin >> input;
    int value = parseInt(input);
    cout << input << endl << value;
    return 0;
}