Leap year calculation problem solving | HackerRank

"""
Task

Given a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise, return False.
"""

#Code:

def is_leap(year):
    leap = False

    # Write your logic here
    if ((year % 400 == 0) or (year % 4 == 0) and (year % 100 !=0)):
        leap = True

    return leap