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01. Pipes In Pool

May 10th, 2019
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Python 0.75 KB | None | 0 0
  1. v = int(input()) # obem na baseina
  2. p1 = int(input()) # debit na parvata traba za chas
  3. p2 = int(input()) # debit na vtorata traba za chas
  4. h = float(input()) # broi chasove v koito otstsustva
  5.  
  6. v1 = (p1 + p2 )* h # napulneni litri
  7. p1_debit = p1 * h # kolko e napulnila traba 1
  8. p2_debit = p2 * h # kolko e napulnila traba 2
  9. p1_procent = (p1_debit / v1) * 100  # kolko procenta e napulnila traba 1
  10. p2_procent = (p2_debit / v1) * 100 # kolko procenta e napulnila traba 2
  11. basein = (v1 / v ) * 100 # kolko procenta e palen baseina
  12. prelql = v1 - v # kolko e prelql baseina
  13.  
  14. if v1 <= v:
  15.     print(f"(The pool is {basein:.2f}% full. Pipe 1: {p1_procent:.2f}%. Pipe 2: {p2_procent:.2f}%.)")
  16. else:
  17.     print(f"(For {h} hours the pool overflows with {prelql} liters.)")
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