"""
Please provide full program code (on Python language)
of parse_number(num) function which returns the dict with
following structure: {odd: number of digits in input value,
even: number of even digits of input value} or false when
wrong input value.serialize.
num - input number

print parse_number(34567)
{'odd':3, 'even':2}
print parse_number(100)
{'odd':1, 'even':2}
print parse_number('word')
False
"""

def pase_number(number):
    number_list = list(str(number))
    # print(number_list)
    odd = []
    even = []
    try:
        for i in number_list:
            i = int(i)
            if i % 2 == 0:
                even.append(i)
            elif i % 2 != 0:
                odd.append(i)
    except ValueError:
        pass
        # print(False)
    if even.__len__() != 0 and odd.__len__() != 0:
        return {"odd": odd.__len__(), "even": even.__len__()}
    else:
        return False


print(pase_number(100))
print(pase_number("avs"))
print(pase_number(123456))