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antoshka1312

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Sep 27th, 2017
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  1. [ENABLE]
  2. //code from here to '[DISABLE]' will be used to enable the cheat
  3. alloc(newmem,2048)
  4. label(returnhere)
  5. label(originalcode)
  6. label(exit)
  7.  
  8. newmem:
  9. cmp dword ptr [eax+0x15e0],0x0
  10. je 0047919A
  11.  
  12. originalcode:
  13. movzx ecx,byte ptr [esi+02]
  14. lea edx,[ebx+000015DC]
  15.  
  16. exit:
  17. jmp returnhere
  18.  
  19. 004790AA:
  20. jmp newmem
  21. nop
  22. nop
  23. nop
  24. nop
  25. nop
  26. returnhere:
  27.  
  28.  
  29.  
  30.  
  31.  
  32. [DISABLE]
  33. //code from here till the end of the code will be used to disable the cheat
  34. dealloc(newmem)
  35. 004790AA:
  36. movzx ecx,byte ptr [esi+02]
  37. lea edx,[ebx+000015DC]
  38. //Alt: db 0F B6 4E 02 8D 93 DC 15 00 00
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