Headers in dataset (Matlab)
dmsdb = dataset({ 'John','Name'},{'Amsterdam','City'},{10,'number' });
produces:
    Name    City         number
    John    Amsterdam    10 --> Headers are good!

dmsdb(1,1:3) = dataset({ cellstr('John'),'Name'},{cellstr('Amsterdam'),'City'},{10,'number' });
Produces:
    Var1          Var2               Var3
    'John'        'Amsterdam'        10

data = dataset({[], 'Name'}, {[], 'City'}, {[], 'number'});

data = dataset([], [], [], 'VarNames', {'Name', 'City', 'number'});

>> data

data =

[empty 0-by-3 dataset]

>> get(data, 'VarNames')

ans =

    'Name'    'City'    'number'

>> data = [data; dataset({'John'}, {'Amsterdam'}, 10, 'VarNames', get(data, 'VarNames'))]

data =

    Name          City               number
    'John'        'Amsterdam'        10

>> dmsdb = dataset({ {'John'},'Name'},{{'Amsterdam'},'City'},{10,'number' });

dmsdb =

    Name          City               number
    'John'        'Amsterdam'        10

%# create dataset with no rows
ds = dataset(cell(0,1),cell(0,1),zeros(0,1));
ds.Properties.VarNames = {'Name', 'City', 'number'};

%# adding one row at a time
for i=1:3
    row = {{'John'}, {'Amsterdam'}, 10};  %# construct new row each iteration
    ds(i,:) = dataset(row{:});
end

%# adding a batch of rows all at once
rows = {{'Bob';'Alice'}, {'Paris';'Boston'}, [20;30]};
ds(4:5,:) = dataset(rows{:});

>> ds
ds =
    Name           City               number
    'John'         'Amsterdam'        10
    'John'         'Amsterdam'        10
    'John'         'Amsterdam'        10
    'Bob'          'Paris'            20
    'Alice'        'Boston'           30

vars = {'Name', 'City', 'number'};
ds = [ds ; dataset(rows{:}, 'VarNames',vars)]

% 1) Create the 3 variables of interest, then make the dataset.
% Make sure they are column vectors!
>> Name = {'John' 'Joe'}';  City = {'Amsterdam' 'NYC'}'; number = [10 1]';
>> dataset(Name, City, number)

ans =

    Name          City               number
    'John'        'Amsterdam'        10
    'Joe'         'NYC'               1

% 2) More compact than doing 3 separate cell arrays
>> dataset({{'John' 'Amsterdam' 10} 'Name' 'City' 'number'})

ans =

    Name          City               number
    'John'        'Amsterdam'        [10]