// Answers:
// 1. This is probably not the author's intention, but I didn't call wait(). Sending a signal might also work.

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>

int main(int argc, char *argv[]) {
    int rc = fork();

    if (rc < 0) {
        fprintf(stderr, "fork failed\n");
        exit(1);
    } else if (rc == 0) {
        printf("hello\n");
    } else {
        waitpid(-1, NULL, 0);
        printf("goodbye\n");
    }
    return 0;
}