For anyone coming here in the future, either you can change the date on the computer to get a date in the interval in the file or you have to find the matching date to your current date in the 8 years loop.
Here’s how you can do :

Let
r = (Year – 2002) mod 8
Y′ = 2002 + r
Then
Password(Year–MM–DD) = Password( Y′–MM–DD )

In other words the 2002–2009 table simply repeats every 8 years. To get the code for any date Y–M–D:

Compute r = (Y – 2002) % 8
Set base-year Y′ = 2002 + r (so Y′ is in [2002…2009])
Look up the password for Y′–M–D in the original 2002–2009 list.
Example 2022-02-02:
r = (2022−2002)%8 = 0 → Y′=2002
⇒ password = entry at 2002-02-02 = BDHLC0BA