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Oct 11th, 2019
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  1. SELECT M.METAL_NAME AS "Metal Coat",
  2.        S.STONE_NAME AS "Embedding Gemstone",
  3.        COUNT(*) AS "Placed Orders"
  4. FROM COMPONENT C JOIN JOB J
  5.     ON J.JOB_ID = C.JOB_ID FULL JOIN STONE_TYPE S
  6.     ON S.STONE_ID = C.STONE_ID FULL JOIN METAL_TYPE M
  7.     ON M.METAL_ID = C.METAL_ID
  8. GROUP BY S.STONE_NAME, M.METAL_NAME
  9. ORDER BY COUNT(*) DESC;
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