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Jun 25th, 2019
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  1. let r[0..n] be a new array
  2. r[0] = 0
  3. for j = 1 to n
  4. q = -1
  5. for i = 1 to j
  6. for k = 0 to n-1
  7. q = Math.max(q[n][k], p[i] + q[n-i-1][k-1]);
  8. r[j] = q
  9. return r[n]
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