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django urlencode

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Jan 5th, 2011
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Python 0.53 KB | None | 0 0
  1. try:
  2.         project_list_page = paginator.page(page)
  3.     except (EmptyPage, InvalidPage):
  4.         project_list_page = paginator.page(paginator.num_pages)
  5.  
  6.     if project_list_page.has_previous:
  7.         get_query_dict.__setitem__('page',str(project_list_page.next_page_number()))
  8.         urlquerystring_next_page = get_query_dict.urlencode()
  9.     if project_list_page.has_next:
  10.         get_query_dict.__setitem__('page',str(project_list_page.previous_page_number()))
  11.         urlquerystring_previous_page = get_query_dict.urlencode()
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