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Jun 18th, 2019
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  1. Tengo los campos historia , nombre, apellidos, terapeuta1 y terapeuta2
  2.  
  3. Tengo los campos id, nombre y apellidos.
  4.  
  5. **historia** = 0
  6. **nombre** = prueba
  7. **apellidos** = prueba
  8. **terapeuta1** = 10
  9. **terpauta2** = 5
  10.  
  11. SELECT pa.*, pe.nombre AS nombre_personal FROM pacientes pa INNER JOIN personal pe ON terapeuta1 = id AND terapeuta2 = id
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