ByteBuffer to send bytes in chunks of 8 (only 1 array copy operation)

package com.example;

import java.nio.ByteBuffer;
import java.util.Arrays;

public class ByteBufferTests {

    private ByteBuffer buf = ByteBuffer.allocate(8);

    public static void main(String[] args) {
        ByteBufferTests bbt = new ByteBufferTests();
        bbt.onReceive(new byte[]{1, 2, 3});
        bbt.onReceive(new byte[]{4, 5});
        bbt.onReceive(new byte[]{6, 7, 8});
        bbt.onReceive(new byte[]{9, 10, 11, 12, 13, 14, 15, 16});
        bbt.onReceive(new byte[]{17, 18, 19, 20, 21, 22, 23, 24, 25, 26});

        bbt.buf.flip();
        byte[] bytes = new byte[bbt.buf.remaining()];
        bbt.buf.get(bytes);
        System.out.println("Remaining bytes: " + Arrays.toString(bytes));
    }

    public void onReceive(byte[] bytes) {
        ByteBuffer rBuf = ByteBuffer.wrap(bytes);

        while (true) {
            int maxBytesToRead = Math.min(buf.remaining(), rBuf.remaining());
            for (int i = 0; i < maxBytesToRead; i++) {
                buf.put(rBuf.get());
            }
            if (buf.remaining() == 0) {
                byte[] nextBytes = buf.array();
                System.out.println("onNext(" + Arrays.toString(nextBytes) + ")");
                buf = ByteBuffer.allocate(8);
            } else {
                break;
            }
        }
    }

}