sin equation solver python

graph1: 1  sin(x +  0 ) +  0
graph2: 2  sin(x +  0 ) +  0
graph3: 1 sin(x +  0 ) +  3
graph4: 1 sin(x +  180 ) +  0

def most_frequent(List):
    counter = 0
    num = List[0]

    for i in List:
        curr_frequency = List.count(i)
        if(curr_frequency> counter):
            counter = curr_frequency
            num = i

    return num


def find_equation(graph):
    min_value = 10000
    max_value = 1
    values = []

    for coord in graph:
        #we dont need to find the min value, as it'll be the max value but with a changed sign
        if max_value < coord[1]:
            max_value = coord[1]
        if min_value > coord[1]:
            min_value = coord[1]
        values.append(coord[1])
    normal = int((min_value + max_value)/2)
  #  print("Normal: ", normal)
    coef = max_value - normal
 #   print("Max_value: ", max_value)
 #   print("Coef:", coef)

    step = values[1] - values[0]
 #   print("Step:", step)


    if step != 1:
        values = list(map(lambda x: int(x/step), values))
    if normal != 0:
        values = list(map(lambda x: x-normal, values))


#    print("Values:", values)

    real_values = [0, 1, 0, -1, 0]
    counter = 0
    if real_values != values:
        for value in values:
            counter += 1
            if value == 0:
                break
       # print("move by", counter)
#    print(values)

    print(coef, "sin(x + ", 90*counter, ") + ", normal)


graph1 = [(0, 0), (90, 1), (180, 0), (270, -1), (360, 0)]
graph2 = [(0, 0), (90, 2), (180, 0), (270, -2), (360, 0)]
graph3 = [(0, 3), (90, 4), (180, 3), (270, 2), (360, 3)]
graph4 = [(0, 1), (90, 0), (180, -1), (270, 0), (360, 1)]


find_equation(graph1)