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Feb 9th, 2017
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  1. private void insertData()
  2. {
  3. string conStr = "server=127.0.0.1;user=root;" +
  4. "database=test;password=123;";
  5. using (MySqlConnection con = new MySqlConnection(conStr))
  6. {
  7. try
  8. {
  9. string sql = "INSERT INTO friends (name, lastname, age)" +
  10. "VALUES (@Name, @LastName, @Age);";
  11. con.Open();
  12. MySqlCommand cmd = new MySqlCommand(sql, con);
  13. //создаем параметры и добавляем их в коллекцию
  14. cmd.Parameters.AddWithValue("@Name", "Vasya");
  15. cmd.Parameters.AddWithValue("@LastName", "Pupkin");
  16. cmd.Parameters.AddWithValue("@Age", 18);
  17. cmd.ExecuteNonQuery();
  18. }
  19. catch (Exception ex)
  20. {
  21. MessageBox.Show(ex.Message);
  22. }
  23. }
  24. }
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