02. Equal Sums Even Odd Position

function solve(input) {
  let firtNum = Number(input[0]);
  let secondNum = Number(input[1]);

  let output = ""

  for (let i = firtNum; i <= secondNum; i++) {
    // 100000
    let numberAsString = i.toString();
    let evenSum = 0;
    let oddSum = 0;

    for (let index = 0; index < numberAsString.length; index++) {
      let currentNumber = Number(numberAsString[index]);

      if (index % 2 === 0) {
        evenSum += currentNumber;
      } else {
        oddSum += currentNumber;
      }
    }

    if (evenSum === oddSum) {
      output += i + " "
    }
  }

  console.log(output)
}