#include "stdafx.h"
#include <cstdlib>
#include <string>
#include <stdio.h>
#include <iostream>
#include <conio.h>
#include <fstream>
#include <math.h>
#include <cstdio>
using namespace std;

int value(char Roman) //Roman is the character that is presented from the integer value.
{

		switch (Roman) //Switch statement that presents a number in return of the user input
		{
		case 'I':
			return 1; //If I is presented, 1 is returned.
		case 'V':
			return 5; //If V is presented, 5 is returned.
		case 'X':
			return 10; //If X is presented, 10 is returned.
		case 'L':
			return 50; //If L is presented, 50 is returned.
		case 'C':
			return 100; //If C is presented, 100 is returned.
		case 'D':
			return 500; //If D is presented, 500 is returned.
		case 'M':
			return 1000; //If M is presented, 1000 is returned.
		}
	}
	int convert1(string roman) { //The function "convert1" showcases how the position each roman numeral is in changes the result.
		int SecNum = value(roman[1]);//the variables of the function
		int FirNum = value(roman[0]);
		if (FirNum < SecNum) { //If the first number of the code is smaller than the second, they will produce a negative.
			return SecNum - FirNum;
		}
		else return SecNum + FirNum; //However if the first number is larger, they will produce a positive.
	}
	int convert2(string roman) { //The function "convert2" will work for any roman numeral with more than two characters and for the 'I' variable.
		int sum = value(roman[roman.length() - 1]);
		int CurNum;
		int LastNum = value(roman[roman.length() - 1]); //The variables that showcase the current number, last number and the overall sum of the roman numerals converted to produce the final number.

		for (int a = roman.length() - 2; a >= 0; a--) {
			CurNum = value(roman[a]);
			if (LastNum > CurNum) {
				sum = sum - CurNum; //If the last number in the code is larger than the current number, they will take away from eachother.
			}
			else if (LastNum <= CurNum) {
				sum = sum + CurNum; //However, if the last number is smaller or equal to the previous, they will add.
			}
			LastNum = CurNum;
		}
		return sum; //The sum is returned.

	}
	int main()
	{
		FILE *file_in; //Defining the file variable
		file_in = fopen("roman.txt", "r"); //Reading the file that all the numbers are on
		int Number;
		char Numeral[20];
		fscanf(file_in, "%s, %d", Numeral, &Number);
		string select;
		string A = "1. Batch Mode";
		string B = "2. User Input mode";
		cout << "Please select from the menu" << endl; //Allows the user to select between Batch Mode and Input Mode
		cout << A << endl;
		cout << B << endl;
		cin >> select;
		{
		if (select == "1") //If 1 is selected, the Batch Mode will be enabled.
		{
			ofstream file;
			file.open("convert.txt"); //Opening the file that the answer will be printed on.
			string Roman; //Compiling the string Roman to the final result.
			printf("Enter the Roman Numeral you would like to convert: ");
			getchar(); //Gets the characters from the printf
			getline(cin, Roman); //Asking the user to input the Roman Numeral they are trying to convert and scanning the string so that the final result can be displayed.

			if (Roman.length() == 1) { //If the final value is equal to 1 roman letter, the function of Roman[0], which is the first number, is presented.
				file << value(Roman[0]) << "\n"; //We use file here so it gets printed out into the file.
			}
			if (Roman.length() == 2) {
				file << convert1(Roman) << "\n"; //If the final value is equal to 2 roman letters, the function of "convert1" is presented, which adds or takes away depending on the number order.
			}
			if (Roman.length() > 2) { //If the final value is more than 2 roman letters, the function of "convert2" is presented, which uses the code LastNum to complete the code.
				file << convert2(Roman) << "\n";
			}
			return 0;
			_getch;
			file.close(); //Making sure the files are closed.
		}
	}

		if (select == "2") //If 2 is selected, the Input Mode will be enabled.
		{

			string Roman;
			printf("Enter the Roman Numeral you would like to convert: ");
			getchar();
			getline(cin, Roman); //Asking the user to input the Roman Numeral they are trying to convert and scanning the string so that the final result can be displayed.
			if (Roman.length() == 1) {
				cout << value(Roman[0]) << "\n"; //If the final value is equal to 1 roman letter, the function of Roman[0], which is the first number, is presented.
			}
			if (Roman.length() == 2) {
				cout << convert1(Roman) << "\n"; //If the final value is equal to 2 roman letters, the function of "convert1" is presented, which adds or takes away depending on the number order.
			}
			if (Roman.length() > 2) {
				cout << convert2(Roman) << "\n"; //If the final value is more than 2 roman letters, the function of "convert2" is presented, which uses the code LastNum to complete the code.
			}
			return 0;
			_getch;
		}
	}

	/*
	switch (Roman) - This switch statement allows the user's inputted roman numeral to be converted depending on what it is.
	convert1 - The function that will change the final result depending on the variables.
	SecNum = The Second Number in the Roman Numeral
	FirNum = The First Number in the Roman Numeral
	Roman[0] = If the Roman Numeral only has 1 digit, then that is the only thing printed/converted.
	convert2 - The second function that will change the final result that has more than 2 roman numeral digits.
	Sum = The final sum created by the for loop.
	CurNum = Current Number that is being converted
	LastNum = The previous number that will be added/subtracted depending on its position
	string Roman = The string from the previous functions that will be displayed at the end.
	getline = Taking the line from Roman and presenting it out on the screen.
	if Roman.length = 1 : The first number will be presented
	if Roman.length = 2 : The convert1 function will be used.
	if Roman.length = > 2 : The convert2 function will be used.
	file << : All of these make the presented final number appear inside a file instead of the screen.
	*/