from itertools import *
def f(a, b, c):
    return (a and (not(c))) or ((not(b)) and (not(c)))
table = [(0, 0, 0), (0, 0, 1), (0, 1, 0), (0, 1, 1), (1, 0, 0), (1, 0, 1), (1, 1, 0), (1, 1, 1)]
for p in permutations('abc'):
    if [f(**dict(zip(p, r))) for r in table] == [1, 0, 0, 0, 1, 0, 1, 0]:
        print(p)