reverseNumber

#include <stdio.h>
#include <math.h>       /* log10 */

int main()
{

    int originalNumber = 472;

    // get number of 10's in the provided number, that's gives an idea as to what the length of the number is
    int log10ofOriginalNumber = log10(originalNumber);

    int reversedNumber = 0;

    // In theory, it works like this -> 200 + 70 + 4
    // loop according to length of number (from log10);
    for (int i = 0; i <= log10ofOriginalNumber; i++) {
        // last digit => (originalNumber % 10), decimal place -> (reversedNumber*10)
        reversedNumber = reversedNumber*10 + originalNumber % 10;

        // remove the current last number from originalNumber
        originalNumber = originalNumber / 10;

    }

    printf("reversed number is:: %d", reversedNumber);

    return 0;
}