Resolving Power of a Telescope

%% Resolving Power of a Telescope
% Determines the smallest diameter of the objective lens required to resolve and
% object on the moon

% Inputs and Variables
d = input('Earth to moon distance\n');
r = input('Object on the moon\n');
lambda = input('Wavelength\n');

% Outputs and Equations
theta = 1.22*d*lambda/r;
fprintf('The diameter: %.3e m\n', theta)