Advertisement
askarulytarlan

Askar

Nov 3rd, 2017
90
0
Never
Not a member of Pastebin yet? Sign Up, it unlocks many cool features!
text 2.05 KB | None | 0 0
  1. #include <bits/stdc++.h>
  2.  
  3. using namespace std;
  4.  
  5. int n, a[3][7], pr[1500];
  6.  
  7. int main(){
  8. cin >> n;
  9. for(int i = 0; i <= 2; i++){
  10. for(int j = 0; j < 7; j++){
  11. a[i][j] = 0;
  12. }
  13. }
  14. for(int i = 0; i < n; i++){
  15. for(int j = 1; j <= 6; j++){
  16. cin >> a[i][j];
  17. }
  18. }
  19. for(int i = 1; i <= 6; i++){
  20. if(!a[0][i])
  21. continue;
  22. pr[a[0][i]] = 1;
  23. if(n >= 2){
  24. for(int j = 0; j <= 6; j++){
  25. pr[a[0][i]*10+a[1][j]] = 1;
  26. if(n == 3){
  27. for(int l = 0; l <= 6; l++){
  28. pr[a[0][i]*100+a[1][j]*10+a[2][l]] = 1;
  29. }
  30. }
  31. }
  32. for(int j = 0; j <= 6; j++){
  33. pr[a[0][i]*10+a[2][j]] = 1;
  34. if(n == 3){
  35. for(int l = 0; l <= 6; l++){
  36. pr[a[0][i]*100+a[2][j]*10+a[1][l]] = 1;
  37. }
  38. }
  39. }
  40. }
  41. }
  42. for(int i = 1; i <= 6; i++){
  43. if(!a[1][i])
  44. continue;
  45. pr[a[1][i]] = 1;
  46. if(n >= 2){
  47. for(int j = 0; j <= 6; j++){
  48. pr[a[1][i]*10+a[0][j]] = 1;
  49. if(n == 3){
  50. for(int l = 0; l <= 6; l++){
  51. pr[a[1][i]*100+a[0][j]*10+a[2][l]] = 1;
  52. }
  53. }
  54. }
  55. for(int j = 0; j <= 6; j++){
  56. pr[a[1][i]*10+a[2][j]] = 1;
  57. if(n == 3){
  58. for(int l = 0; l <= 6; l++){
  59. pr[a[1][i]*100+a[2][j]*10+a[0][l]] = 1;
  60. }
  61. }
  62. }
  63. }
  64. }
  65. for(int i = 1; i <= 6; i++){
  66. if(!a[2][i])
  67. continue;
  68. pr[a[2][i]] = 1;
  69. if(n >= 2){
  70. for(int j = 0; j <= 6; j++){
  71. pr[a[2][i]*10+a[0][j]] = 1;
  72. if(n == 3){
  73. for(int l = 0; l <= 6; l++){
  74. pr[a[2][i]*100+a[0][j]*10+a[1][l]] = 1;
  75. }
  76. }
  77. }
  78. for(int j = 0; j <= 6; j++){
  79. pr[a[2][i]*10+a[1][j]] = 1;
  80. if(n == 3){
  81. for(int l = 0; l <= 6; l++){
  82. pr[a[2][i]*100+a[1][j]*10+a[0][l]] = 1;
  83. }
  84. }
  85. }
  86. }
  87. }
  88.  
  89. for(int i = 1; i <= 1000; i++){
  90. if(!pr[i]){
  91. cout << i-1 << endl;
  92. return 0;
  93. }
  94. }
  95. }
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement