3 subredes por tanto averiguamos
que eso corresponde a 2 bits:
Entonces iteramos los 2 bits:
0000000 1 = 191.190.0.0		id red
0000001 1 = 191.190.0.1 	pc 1
							...
0011110 1 = 191.190.0.62 	pc 62
0011110 1 = 191.190.0.63 	broad subred
(2^6)-2 = 64 - 2 = 62

0100000 2 = 191.190.0.64 id subred
0111111 2 = 191.190.0.127 broad subred
(2^6)-2 = 64 - 2 = 62

1000000 3 = 191.190.0.128
1011111 3 = 191.190.0.191
(2^6)-2 = 64 - 2 = 62

1100000 4 = 191.190.0.192
1111111 4 = 191.190.0.254
(2^6)-2 = 64 - 2 = 62