pyTextBasedCalculator

# A simple text based calculator project in Python
# This is a common student task

def get_float(prompt):
    while True:
        s = input(prompt)
        try:
            return s, float(s)      # here I return the original string AND the float value
        except:
            print("Invalid input\n")
            # here the code loops back to request input again


while True:
    print("A: Add\nS: Subtract\nM: Multiply\nD: Divide \nP: Power \nR: Remainder\nQ: Quit")
    while True:
        op = input("Select an operation: ")
        op = op.upper()[0]
        if op in ['A', 'S', 'M', 'D', 'P', 'R', 'Q']:
            break
        print("Operation not recognised\n")

    if op == "Q":
        break

    usera, a = get_float("Enter first number: ")
    userb, b = get_float("Enter second number: ")
    # Find out if both user inputs were integers
    both_int = a == int(a) and b == int(b)
    if op in "DR" and b == 0.0:         # b must not be zero for division or remainder operations
        print("******* Divide by zero error *******\n")
        continue

    if op == "A":
        # Show the original user input strings, to avoid confusion between floats and integers
        if both_int:
            print(f"{usera} plus {userb} equals {int(a + b)}")
        else:
            print(f"{usera} plus {userb} equals {a + b:.02f}")
    elif op == "S":
        if both_int:
            print(f"{usera} minus {userb} equals {int(a - b)}")
        else:
            print(f"{usera} minus {userb} equals {a - b:.02f}")
    elif op == "M":
        if both_int:
            print(f"{usera} times {userb} equals {int(a * b)}")
        else:
            print(f"{usera} times {userb} equals {a * b:.02f}")
    elif op == "D":
        print(f"{usera} divided by {userb} equals {a / b:.02f}")
    elif op == "P":
        print(f"{usera} to the power of {userb} equals {a ** b:.02f}")
    elif op == "R":
        # Remainder operation requires integers only
        if int(a) != a or int(b) != b:
            print("Integers only for this operation")
        else:
            print(f"{usera} divided by {userb} gives a remainder of {int(a) % int(b)}")
    input("\nPress enter to continue ")

print("Goodbye")