Lindrian

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Dec 15th, 2013
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  1. map :: (a -> b) -> [a] -> [b]
  2. zipWith :: (a -> b -> c) -> [a] -> [b] -> [c]
  3.  
  4. map.a == (a -> b -> c)
  5. map.b == [a] -> [b] -> [c]
  6.  
  7. map zipWith :: ((a -> b -> c) -> [a] -> [b] -> [c]) -> [(a -> b -> c)] -> [[a] -> [b] -> [c]]
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