Project Euler#48 Self powers

#The series, 1**1 + 2**2 + 3**3 + ... + 10**10 = 10405071317.

#Find the last ten digits of the series, 1**1 + 2**2 + 3**3 + ... + 1000**1000.

count = 0
for i in range(1,1001):
    count += i**i
print count