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Aug 5th, 2018
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PL/SQL 0.27 KB | None | 0 0
  1. SELECT CUSTOMER, MAX(LAST_CALL_DUR), MAX(MAX_DUR)
  2. FROM
  3. (SELECT CUSTOMER,
  4.        FIRST_VALUE (DURATION) OVER (PARTITION BY CUSTOMER ORDER BY CALL_DATE DESC) AS LAST_CALL_DUR,
  5.        MAX(DURATION) OVER (PARTITION BY CUSTOMER) MAX_DUR
  6. FROM PHONE_CALLS)
  7. GROUP BY CUSTOMER;
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