Kwwiker

Вот как-то так можно

Mar 7th, 2021
721
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  1. for i in range(30001, 70001):
  2.     for j in range(1, i+1):
  3.         if i % j == 0:
  4.             del += 1
  5.     if del > 17:
  6.         count += 1
  7.         if min > i:
  8.             min = i
  9.     del := 0
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