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Mar 29th, 2020
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  1. int sol(string s) {
  2. int rhs = 0, lhs = 0;
  3. for (int i = 0; i < s.size(); ++i) if (s[i] == 'A') ++rhs;
  4. // rhs equals number of A's after index i [inclusive]
  5. // lhs equals number of B's before index i [exclusive]
  6. int ans = rhs;
  7. for (int i = 0; i < s.size(); ++i) {
  8. if (s[i] == 'A') --rhs;
  9. else ++lhs;
  10. ans = min(ans, rhs + lhs);
  11. }
  12. return ans;
  13. }
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