import math
a, b, c = map(float, input('個別輸入三個數分開空格').split())
B = b*b-4*a*c
def qr(a, b, c):
    if not all(isinstance(i, (int, float)) for i in [a, b, c]):
        raise typeError('wrong')
        return
    if B < 0:
        print('no')
    elif B == 0:
        result = -b/(2*a)
        print('有相同兩個解', result)
    else:
        return(-b+math.sqrt(b*b-4*a*c))/(2*a), (b+math.sqrt(b*b-4*a*c))/(2*a)
        print('有不同兩個解', qr(a, b, c))
qr(a, b, c)