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- df %>%
- group_by(col_a, col_b) %>%
- summarise( a = sum(col_a == 'a'),
- b = sum(col_a == 'b'),
- c = b/a
- )
- df.groupby('id').agg({'out':[lambda x:sum(x==4)]})
- df.assign(out=df.out==4).groupby('id').agg({'out':sum})
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