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Nov 12th, 2019
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  1. xmin=2;
  2. xmax=11;
  3. nbPts=10;
  4. T = (xmax-xmin);
  5. h = T/(nbPts-1);
  6.  
  7. for i=1:nbPts
  8.  
  9. x(i)=xmin+(T/(nbPts-1))*(i-1);
  10. y(i) = 2*x(i).^3 ;
  11.  
  12. end
  13.  
  14. der = diff(y)/h;
  15.  
  16. figure(1)
  17. hold on;
  18. plot(x,y);
  19. plot(x(:,1:end-1),der); %Vue que la matrice der est plus petite que celle de x, on prend l'avant dernière valeur de x
  20. end
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