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#pragma hdrstop
#pragma argsused

#ifdef _WIN32
#include <tchar.h>
#else
  typedef char _TCHAR;
  #define _tmain main
#endif

#include <stdio.h>
#include <iostream>
#include <conio.h>
#include <string>

using namespace std;

void inputNumInBase12(char*Num12)
{
	cout << "Enter 12-base num( it must be lesser or equal to 41A792678515120367), using digits and symbol 'A', 'B'."<<endl;
	cin.getline(Num12,19);
	cout << "u've entered "<< Num12;
}

int conwert12DigitsTo10(char digit12)
{
	if ((digit12!='A')&&(digit12!='B')) {
		return (digit12-'0');
	}
	else if (digit12!='A')
	{
		return 11;
	}
	else return 10;
}

long long conwerBasefrom12To10(char*base12){
	int length = strlen(base12);
	long long res=0;
	for (int i = 0; i < length; i++)
	{
		res=res*12+conwert12DigitsTo10(*base12);
	   //	cout << "\ndigit12"<<i<<" = "<<conwert12DigitsTo10(*base12);
		//cout << "\nres"<<i<<" = "<<res;
		base12++;
	}
	return res;
}

void conwertBase10To9(char * base9, long long base10)
{
	int i= 0;
	do{
		base9[i]=char(base10%9+'0');
		base10/=9;
		i++;
	}while (base10);
	base9 = strrev(base9);
}

int conwert12DigitIn10Nums()
{
	char a = getch();
	if (int(a)==13)
	{
		return -1;
	}
	cout<<a;
	if (a=='A') {
		return 10;
	}
	if (a=='B') {
		return 11;
	}
	return (a-'0');

}

long long enterNumIn12BaseWithoutMassAndConwertItIn10BaseNum()
{
	long long res = 0;
	cout << "Enter 12-base num( it must be lesser or equal to 41A792678515120367), using digits and symbol 'A', 'B'."<<endl;
	for (int i = 0; (i < 20); i++) {
		int digit = conwert12DigitIn10Nums();
		if (digit==-1) {
			break;
		}
		res=res*12+digit;
	}
	return res;
}

void conwert10BaseTo9WithoutArray(long long base10)
{
	int ans;
	int i = 0;
	cout << "In base9: ";
	long long ink = base10;
	do{
		ink/=9;
		i++;
	}while(ink!=0);
	for (int j =i ; j >0; j--) {
		long long incr = base10;
		for (int k = 0; k< j-1;k++ )
		{
			incr/=9;
		}
		cout <<char(incr%9+'0');
	}

}
int _tmain(int argc, _TCHAR* argv[])
{
	cout << "This program convert 12-base nums into 9-base nums"<<endl;
	char base12[19]={'\0'};
	inputNumInBase12(base12);
	long long base10=conwerBasefrom12To10(base12);
	cout<<"\nbase10 "<<base10;
	char base9[21]={'\0'};
	conwertBase10To9(base9, base10);
	cout << "\nbase9 : "<< base9;
	cout << "\n\nNow this program will solve the same problem without using arrays.";
	long long base10two = enterNumIn12BaseWithoutMassAndConwertItIn10BaseNum();
	cout << "\n\nbase10two "<< base10two;
	cout <<endl;
	conwert10BaseTo9WithoutArray(base10two);
	getch();
	return 0;
}