anagram hashtable solution

from collections import Counter
from typing import List


def find(words: List[str], needle: str) -> str:
    needle_frequency = Counter(needle)

    for word in words:
        if len(word) <= len(needle):
            word_frequency = Counter(word)
            matched_word = word
            for key in word_frequency.keys():
                if key not in needle_frequency or needle_frequency[key] < word_frequency[key]:
                    matched_word = ""
                    break
            if len(matched_word):
                return matched_word
    return "-"


print(find(["baby", "referee", "cat", "dada", "dog", "bird", "ax"], "ctay"))