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Apr 23rd, 2017
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  1. ID score
  2. 100 1
  3. 100 2
  4. 102 6
  5. 102 8
  6. 102 12
  7. 103 4
  8. 103 7
  9.  
  10. ID score result
  11. 100 1 NaN*
  12. 100 2 1
  13. 102 6 NaN
  14. 102 8 2
  15. 102 12 4
  16. 103 4 NaN
  17. 103 7 3
  18.  
  19. df['result'] = df.groupby('ID')['score'].transform('diff')
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