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May 22nd, 2018
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  1. Zadanie 1
  2.  
  3.  
  4.  
  5.  
  6. Zadanie 2
  7.  
  8. SELECT emp_no
  9. FROM works_on
  10. WHERE (enter_date < '2007-01-01') or (enter_date > '2007-12-31')
  11.  
  12.  
  13.  
  14.  
  15. Zadanie 3
  16.  
  17. select emp_no, emp_lname
  18. from employee
  19. where emp_fname like '%t%t%'
  20.  
  21.  
  22.  
  23. Zadanie 4
  24.  
  25. USE dbjoin
  26. SELECT emp_no from dbo.employee e inner join dbo.department d
  27. ON e.dept_no=d.dept_no where d.location='Seattle'
  28.  
  29.  
  30. Zadanie 5
  31.  
  32.  
  33. When grouping column contains a null value, that row becomes a group in the results and if grouping column contains more than one null value, the null values are put into a single group.
  34.  
  35.  
  36. Zadanie 6
  37.  
  38. COUNT(*) operation counts all rows fed to it by execution plan branch under it /// COUNT(column) operation counts all non-null values in that column from rows fed to it by execution plan branch under it
  39.  
  40.  
  41. Zadanie 7
  42.  
  43. USE dbjoin
  44. SELECT MAX(emp_no) from employee
  45.  
  46.  
  47. Zadanie 8
  48.  
  49. SELECT job FROM works_on
  50.  
  51. where emp_no in (select emp_no from works_on group by
  52.  
  53. emp_no having COUNT(emp_no)>1)
  54.  
  55.  
  56.  
  57. Zadanie 9
  58.  
  59. SELECT emp_no, job FROM works_on w INNER JOIN project p ON w.project_no=p.project_no WHERE p.project_name='Gemini'
  60.  
  61.  
  62. Zadanie 10
  63.  
  64. SELECT DISTINCT emp_fname, emp_lname FROM project p
  65. INNER JOIN works_on w ON p.project_no=w.project_no
  66. INNER JOIN employee e ON w.emp_no=e.emp_no
  67. INNER JOIN department d ON e.dept_no=d.dept_no
  68. WHERE d.dept_name='Accounting' or d.dept_name='Research'
  69.  
  70.  
  71. Zadanie 11
  72.  
  73. select enter_date from works_on w inner join employee e on w.emp_no=e.emp_no where e.dept_no='d1'
  74.  
  75.  
  76.  
  77. Zadanie 12
  78.  
  79. select project_name from project
  80. where project_no in (select project_no from works_on group by project_no having COUNT(emp_no)>=2)
  81.  
  82.  
  83. ZAdanie 13
  84.  
  85. SELECT emp_fname, emp_lname FROM employee e
  86. INNER JOIN works_on d ON e.emp_no=d.emp_no
  87. INNER JOIN project p ON d.project_no=p.project_no
  88. WHERE p.project_name='Mercury' and d.job= 'manager'
  89.  
  90. Zadanie 14
  91.  
  92.  
  93. SELECT emp_no FROM employee e
  94. INNER JOIN department d ON e.dept_no=d.dept_no
  95. WHERE d.dept_name='marketing'
  96.  
  97. Zadanie 15
  98.  
  99.  
  100. CREATE TABLE project_temp (project_no INTEGER NOT NULL,
  101. project_name CHAR(20) NOT NULL,
  102. budget CHAR(20) NOT NULL,)
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