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May 26th, 2018
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  1. LEFT JOIN
  2. (
  3. SELECT
  4. COUNT(b.id) AS c_id,
  5. LEFT(b.start_date, 10) AS date,
  6. b.professional_user_id
  7. FROM patient_doctor pd
  8. GROUP BY date
  9. UNION SELECT
  10. COUNT(c.id) AS c_id,
  11. LEFT(c.inactivation_date, 10) AS date,
  12. c.professional_user_id
  13. FROM patient_doctor pd
  14. GROUP BY date
  15. ) x
  16. ON x.professional_user_id = a.id
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