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Mar 23rd, 2019
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  1.  
  2. var
  3. s:array[1..5] of integer;
  4. n,k101,count,i,j:integer;
  5. a:integer;
  6. begin
  7. readln(n);
  8. for i:=1 to 5 do readln(s[i]);
  9.  
  10. count := 0;
  11. k101 := 0;
  12. for i:=6 to n do
  13. begin
  14. if(s[1] mod 101 = 0) then inc(k101);
  15. readln(a);
  16. if(a mod 101 = 0) then count := count + i - 5
  17. else count := count + k101;
  18.  
  19. for j:=1 to 4 do
  20. begin
  21. s[j] := s[j+1];
  22. end;
  23. s[5] := a;
  24. end;
  25.  
  26. writeln((n-5+1)*(n-5)div 2 - count);
  27.  
  28. end.
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