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informaticage

min diag

Mar 30th, 2021
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C++ 0.60 KB | None | 0 0
  1. #include <iostream>
  2. #define N 3
  3.  
  4. using namespace std;
  5.  
  6. int main() {
  7.   int M[N][N];
  8.  
  9.   for (int i = 0; i < N; i++) {
  10.     for (int j = 0; j < N; j++) {
  11.       cin >> M[i][j];
  12.     }
  13.   }
  14.  
  15.   // Diagonale principale
  16.   // i == j
  17.   int dmin = M[0][0];
  18.   for (int i = 0; i < N; i++) {
  19.     dmin = M[i][i] < dmin ? M[i][i] : dmin;
  20.   }
  21.  
  22.   // Diagonale secondaria
  23.   // i = N - i - 1
  24.   int dmin2 = M[0][N - 1];
  25.   for (int i = 0; i < N; i++) {
  26.     dmin2 = M[i][N - i - 1] < dmin2 ? M[i][N - i - 1] : dmin2;
  27.   }
  28.  
  29.   cout << "MIN Diag 1: " << dmin << endl << "MIN Diag 2: " << dmin2 << endl;
  30.  
  31.   return 0;
  32. }
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