Farz0l1x

Untitled

Sep 3rd, 2022
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Python 0.21 KB | None | 0 0
  1. for n in range(1, 1000):
  2.     n_2 = bin(n)[2:]
  3.     if int(n_2) % 2 == 0:
  4.         n_2 = n_2 + '10'
  5.     else:
  6.         n_2 = '1' + n_2 + '01'
  7.         R = int(n_2 , 2)
  8.     if R > 441:
  9.         print(n)
  10.         break
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