double numKids = 0;


		for(int i = 0 ; i <numTrials ; i++) {
			//System.out.println("New Couple");
			boolean boy = false;
		boolean girl = false;
			while(boy==false || girl==false) {
				double gender = Math.random();
				if (gender < .5) {
					//System.out.println("Boy");
					numKids= numKids+1;

					boy=true;
				}

				else   {
					//System.out.println("Girl");
					numKids= numKids+1;

					girl=true;
				}
			}
		}double average= numKids/numTrials;
		return average;

	}

	/*
	 * This time, compute the average number of kids a couple needs to have
	 * until they have a "team" of all girls or all boys of the given size.
	 *
	 * For example, if I am looking for a team size of 4, and I have:
	 * girl, boy, boy, boy, girl, boy
	 * Then it took 6 kids before I have a team of 4 of the same gender.
	 *
	 * You can probably copy and paste a large amount of code from the previous problem.
	 */
	public double avgKidsToTeam(int size, int numTrials){

double numKids = 0;


		for(int i = 0 ; i <numTrials ; i++) {
			//System.out.println("New Couple");
			double numboy = 0;
			double numgirl = 0;
			while(numboy <size || numgirl <size) {

				double gender = Math.random();
				if (gender < .5) {
					//System.out.println("Boy");
					numKids= numKids+1;
					numboy= numboy +1;

				}

				else   {
					//System.out.println("Girl");
					numKids= numKids+1;
					numgirl= numgirl +1;

				}
			}
		}double average= size/numKids;
		return average;

	}

	public static void main(String[] args){
		Statistics stats = new Statistics();
		// The largest answer might be anything, but the average should be about 3.
		System.out.println(stats.avgKidsToBoth(1000000));
		// Should be about 2.5
		System.out.println(stats.avgKidsToTeam(2,1000000));
		// Should be about 4.12
		System.out.println(stats.avgKidsToTeam(3,1000000));
		// Should be about 5.81
		System.out.println(stats.avgKidsToTeam(4,1000000));
		// Should be about 7.53
		System.out.println(stats.avgKidsToTeam(5,1000000));
	}

}