EMPLOYEE_ID    EMPLOYEE_NAME      EMPLOYEE_CAR     EMPLOYEE_AGE
     1              Mike             Camry              35
     2              Mark             Civic              33
     3             Helen             Beetle             25

EMPLOYEE_FEEDBACK_ID     EMPLOYEE_ID       FEEDBACK_COMMENT_TX
        1                      1              Very Good
        2                      1              Average
        3                      1              Phenomenal
        4                      2              Okay
        5                      2              NO Comment
        6                      3              Excellent
        7                      3              Hilarious

EMPLOYEE_NAME    EMPLOYEE_CAR     EMPLOYEE_AGE   Comments
 Mike             Camry              35           Very Good Average Phenomenal
 Mark             Civic              33           Okay No Comment
 Helen            Beetle             25           Excellent Hilarious

select employee_name
     , employee_car
     , employee_age
     , listagg(feedback_comment_Tx, ' ') within group (order by e.employee_id)
  from employee e
  join employee_feedback ef ON ef.employee_id = e.employee_id;