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- NewL = [(1.1,[01,02]),(1.2,[03,04]),(1.3,[05,06])]
- L = [[01,02],[03,04],[05,06]]
- OutputList = [1.1,1.2,1.3]
- for val in NewL:
- if NewL[1] == [05,06]:
- print NewL[0]
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