// (0;0) 2018
    // y=kx+b
    // x^2 + (kx+b)^2 = 2018^2
    // (k^2+1) * x^2 + 2*k*b*x + b^2-2018^2 = 0
    //d = 4kkbb - (4kk+4)(bb-2018^2) = 4kkbb - 4kkbb - 4bb + 2018^2*4kk - +2018^2*4 =  2018^2*4kk - 4bb + 2018^2*4
    //  = 4 * ((2018*k - b)(2018*k - b) + 2018^2)
    //  a = k^2+1    b = 2*k*b   c = b^2+2018^2
    // 0 корней d < 0
    // 1 корень d == 0
    // 2 корня  d > 0


#include <iostream>
#include <math.h>

    using namespace std;

    int main()
    {
        int k,b,D=0;
        long double x1=0,x2=0,y1=0,y2=0;
        cin>>k>>b;
        //(k*k+1)*x*x + 2*k*b*x + b*b-2018*2018
        D=((2018*k-b)*(2018*k+b)+2018*2018);
        if (D!=0) {
            if (D>0) {
                x1=(-k*b+sqrt(D))/(k*k+1);
                x2=(-k*b-sqrt(D))/(k*k+1);
                y1=k*x1+b;
                y2=k*x2+b;
                cout<<2<<endl;
                cout<<x1<<" "<<y1<<endl;
                cout<<x2<<" "<<y2;
            }else cout<<0;
        }else {
            x1=-1.0*k*b/(k*k+1);
            y1=k*x1+b;
            cout<<1<<endl;
            cout<<x1<<" "<<y1;
        }
    }