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Aug 22nd, 2019
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  1. values ii
  2. 0 3.0 4
  3. 1 0.0 1
  4. 2 3.0 8
  5. 3 2.0 5
  6. 4 2.0 1
  7. 5 3.0 5
  8. 6 2.0 4
  9. 7 1.0 8
  10. 8 0.0 5
  11. 9 1.0 1
  12.  
  13. bii2=df.groupby(['ii'])['values'].agg(pd.Series.mode)
  14.  
  15. bii3=df.groupby('ii')['values'].agg(lambda x: pd.Series.mode(x)[0])
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