random number with dice arbitrary number Javascript

//Sadale: amigojapan_bnc, maybe this. First roll a die. If n>=4, adds 5 to the next die. Otherwise it's 0. After that, roll the die again. If n<= 5, add n
//with the previous value. If n==6, reroll.
//[01:39am] Sadale: amigojapan_bnc, after this process, you get one digit.
//[01:40am] Sadale: So to get 4 digits, you need to throw 4 times, or more if you encounter 6.
//this can be used to make arbitrary numbers
function getDiceRoll() {//I tested that it generates 1 to 6 by for(i=0;i<10000;i++)if(getDiceRoll()==1) console.log("has 1");
  return Math.round(Math.random() * (6 - 1) + 1);
}
function getDigit(){
    var ret = 0;
    if(getDiceRoll() >= 4){
        ret += 5
    }
    while(true) {
        var value = getDiceRoll();
        if(value <= 5) {
            ret += value;
            if(ret == 10){ // NEW CONDITION!!
                ret = 0
            }
            return ret;
        }
    }
}

for(i=0;i<100;i++){
    console.log(getDigit());
}