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- documentclass[UTF8]{article}
- usepackage{ctex}
- usepackage[a4paper]{geometry}
- usepackage{amsmath}
- usepackage{amssymb}
- usepackage{mdframed}
- usepackage[dvipsnames]{xcolor}
- begin{document}
- begin{enumerate}
- item 设有矩阵$A, B$, 则$r(AB)leqslant min{r(A),r(B)}$.
- item 设有矩阵$A, B$, 则$r(AB)leqslant r(A)$且 $r(AB)leqslant r(B)$.
- item 一个矩阵乘以一个可逆矩阵, 它的秩不会改变.
- item 矩阵的三秩相等.
- item 设有$A_{mtimes n},B_{ntimes s}$, 且$AB=0Rightarrow r(A)+r(B)leqslant n$.
- begin{mdframed}[skipabove = 10pt ,skipbelow = 10pt,leftmargin = 0pt ,rightmargin = 0pt,roundcorner=10pt]
- zihao{-5}fangsongcolor{Red}$[$注$]$: 可以把$B$分成$s$个列向量, 即$B=(alpha_1,alpha_2,ldots,alpha_s)$, 那么$AB=A(alpha_1,alpha_2,ldots,alpha_s)=0$, 这里的$B$就可以看作$Ax=0$的解集.
- end{mdframed}
- item 若$r(A)=n$, 则$r(A^TA)=n$.
- item A是n阶方阵(下面几句话反正也成立).
- $$
- begin{cases}
- 1. Atext{满秩则}A^*text{满秩.}\
- 2. Atext{的秩是}n-1text{则}A^*text{的秩是1.}\
- 3. Atext{的秩小于}n-1text{则}A^*text{的秩是0.}
- end{cases}
- $$
- item $A=alphabeta^TRightarrow r(A)=1$(其中$alphabeta$是任意非0列向量).
- end{enumerate}
- end{document}
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